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Math Help - Placement tests

  1. #1
    Newbie
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    Unhappy Placement tests

    I have to take a placement test for my college orientation, and i have no problem with the highschool level math, but the college level looks rediculous.

    if i post the link then maybe someone could explain how to do it? its really short, not a lot of problems. and the answers are given lol i just cant get to them. Thanks.

    <3 michele

    http://newton.newhaven.edu/soar/math.pdf <-- test

    http://newton.newhaven.edu/soar/mathanswers.pdf <-- answers
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  2. #2
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    Are there any questions in particular you'd like to discuss? Surely you can't be stuck on all of them!
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  3. #3
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    Well how about maybe 2, 3 and 7?
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  4. #4
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    Sure.

    Question 2: We've got a function of x, f(x) =  x^3 - 2x^2 + x - 1. We want f(-x), so write -x in place of x in the expression:

    f(-x) = (-x)^3 - 2(-x)^2 + (-x) - 1 = -x^3 - 2x^2 - x - 1

    using (-x)^2 = x; (-x)^3 = -x.

    (I need to pop out, to anyone else for the others?)
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  5. #5
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    wow thanks, its a lot less scary looking now! your the best!
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  6. #6
    Member Jonboy's Avatar
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    For # 3 whenever you have an expression in the form.. \frac{a}{b}\,=\,\frac{c}{d}..you can multiply diagonally and the following is true.. a\,\cdot\,d\,=\,b\,\cdot\,c

    So we have:.. \frac{3}{1}\,=\,\frac{8\,-\,r}{r}

    Cross multiply:.. (1)(8\,-\,r)\;=\;3r

    Solve for r. You should get 2 for r.

    Now for # 7 are you familiar with the factoring method for quadratics?

    Whenver you have an expression in the form.. ax^2\,+\,bx\,+\,c.. you look for 2 numbers that multiply to get you c and add up to b.

    So our quadratic is:.. \;x^2\,+\,x\,-\,12

    Since a is 1, we always start with this: (x\,+\;\" alt="(x\,+\;\(x\,+\;\" />

    But since c is negative, we now have: (x\,-\;\" alt="(x\,+\;\(x\,-\;\" />

    We know 6\,\cdot\,2=\,12

    Also 12\,\cdot\,1\,=\,12

    Plus 4\,\cdot\,3\,=\,12

    We need the two multiples to add up to 1. These are 4 and -3.

    So the factored form is:.. \boxed{(x\,+\,4)(x\,-\,3)}

    If you have any q's about this message back.
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