
Placement tests
I have to take a placement test for my college orientation, and i have no problem with the highschool level math, but the college level looks rediculous.:confused:
if i post the link then maybe someone could explain how to do it? its really short, not a lot of problems. and the answers are given lol i just cant get to them. Thanks. :o
<3 michele
http://newton.newhaven.edu/soar/math.pdf < test
http://newton.newhaven.edu/soar/mathanswers.pdf < answers

Are there any questions in particular you'd like to discuss? Surely you can't be stuck on all of them!

Well how about maybe 2, 3 and 7?:)

Sure. :)
Question 2: We've got a function of $\displaystyle x$, $\displaystyle f(x) = x^3  2x^2 + x  1$. We want $\displaystyle f(x)$, so write $\displaystyle x$ in place of $\displaystyle x$ in the expression:
$\displaystyle f(x) = (x)^3  2(x)^2 + (x)  1 = x^3  2x^2  x  1$
using $\displaystyle (x)^2 = x; (x)^3 = x$.
(I need to pop out, to anyone else for the others?)

wow thanks, its a lot less scary looking now! your the best! :D

For # 3 whenever you have an expression in the form..$\displaystyle \frac{a}{b}\,=\,\frac{c}{d}$..you can multiply diagonally and the following is true..$\displaystyle a\,\cdot\,d\,=\,b\,\cdot\,c$
So we have:..$\displaystyle \frac{3}{1}\,=\,\frac{8\,\,r}{r}$
Cross multiply:..$\displaystyle (1)(8\,\,r)\;=\;3r$
Solve for $\displaystyle r$. You should get 2 for $\displaystyle r$.
Now for # 7 are you familiar with the factoring method for quadratics?
Whenver you have an expression in the form..$\displaystyle ax^2\,+\,bx\,+\,c$.. you look for 2 numbers that multiply to get you $\displaystyle c$ and add up to $\displaystyle b$.
So our quadratic is:..$\displaystyle \;x^2\,+\,x\,\,12$
Since a is 1, we always start with this: $\displaystyle (x\,+\;\;)(x\,+\;\;)$
But since c is negative, we now have: $\displaystyle (x\,+\;\;)(x\,\;\;)$
We know $\displaystyle 6\,\cdot\,2=\,12$
Also $\displaystyle 12\,\cdot\,1\,=\,12$
Plus $\displaystyle 4\,\cdot\,3\,=\,12$
We need the two multiples to add up to 1. These are $\displaystyle 4$ and $\displaystyle 3$.
So the factored form is:..$\displaystyle \boxed{(x\,+\,4)(x\,\,3)}$
If you have any q's about this message back.