# Sketching complex plane

• Oct 18th 2010, 02:30 PM
SyNtHeSiS
Sketching complex plane
Sketch the subset of the complex plane:

{z E C: |z - 1| = |z - i| }

I have no idea what to do. Could someone please explain?
• Oct 18th 2010, 03:10 PM
Quote:

Originally Posted by SyNtHeSiS
Sketch the subset of the complex plane:

{z E C: |z - 1| = |z - i| }

I have no idea what to do. Could someone please explain?

The modulus of a complex number is it's distance from the origin in the complex plane.
Pythagoras' theorem calculates the distance.

$z=x+iy$

$z-1=(x-1)+iy\Rightarrow\ |z-1|=\sqrt{(x-1)^2+y^2}=\sqrt{x^2+y^2-2x+1}$

$z-i=x+i(y-1)\Rightarrow\ |z-i|=\sqrt{x^2+(y-1)^2}=\sqrt{x^2+y^2-2y+1}$
• Oct 18th 2010, 04:15 PM
Soroban
Hello, SyNtHeSiS!

Did you make a sketch?

Quote:

Sketch the subset of the complex plane: . $\{\,z \in C\!:\;|z - 1| \:=\:|z - i|\,\}$

Hint:

On the Argand diagram:

. . $|z-1|$ is the distance from $\,z$ to $(1,0).$

. . $|z - i|$ is the distance from $\,z$ to $(0,1).$
• Oct 19th 2010, 04:56 AM
SyNtHeSiS
Thanks. Would this sketch be the graph y = x?
• Oct 19th 2010, 08:00 AM