Expand this and solve the quadratic with x.
9 + (x^2 - 18x + 81) = (x^2 -2x + 1)
-18x + 90 = -2x +1
16x = 89
x = 89/16
Now that you've got the x value, find the y values.
I have two circles with equations:
(x - 1)^2 + (y - 4)^2 = 25 and (x - 9)^2 + (y - 4)^2 = 16
And I need to work out where the "lines" of the two circles cross. I can do this fine with a straight line and a circle but how do I do it with two circle equations?
I tried (y-4)^2 same so
(y - 4)^2 = 25 - (x - 1)^2
(y - 4)^2 = 16 - (x - 9)^2
and so 25 - (x - 1)^2 = 16 - (x - 9)^2
But could not seem to get any sensible answer. Can anyone please help me out?
Hello, angypangy!
Find the intersections of: .
Subtract [1] - [2]: .
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Substitute into [1]: .
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The intersections are: .