Solve the following equation involving a determinant
det x (x+2)
9 2x = 0
I did x * 2x - 9(x+2)
It came out to 2x^2 - 9x - 18 = 0
Do I have to do anything else like a quadratic equation? I went to a math tutor and he wasn't sure. I scanned the problem and it's number 11.
http://pic20.picturetrail.com/VOL137.../392720959.jpg

2. Originally Posted by rowdy3
Solve the following equation involving a determinant
det x (x+2)
9 2x = 0
I did x * 2x - 9(x+2)

It came out to $\displaystyle 2x^2 - 9x - 18 = 0$

Do I have to do anything else like a quadratic equation? I went to a math tutor and he wasn't sure. I scanned the problem and it's number 11.
http://pic20.picturetrail.com/VOL137.../392720959.jpg

Hi rowdy3,

The problem said to "solve", so factor it and solve for x.

$\displaystyle 2x^2 - 9x - 18 = 0$

$\displaystyle (2x+3)(x-6)=0$

3. X= -3/2 and and 6. Thanks