Thread: Divide 4x^3 + 2x^2 + 10x - 7 by (x-5).

divide 4x^3 + 2x^2 + 10x - 7 by (x-5) using the long division..

this is polynomial method i think :/.. help please me.. i thought you will understand me.. thanks.. need the answer right now because i will pass this tommorow.. thanks

Are you asking to simplify

?

A simple way to write "x raised to the 3 power" is x^3.

In any case, x divides into 4x^3 4x^2 times. Multiplying all of x- 5 by 4x^2 and subtracting, 4x^3+ 2x^2+ 10x- 7- (4x^2- 20x^2)= 22x^2+ 10x- 7.

x divides into 22x^2 22x times. Multiplying all of x- 5 by 22x and subtracting, 22x^2+ 10x- 7- (22x^2- 110x)= 120x- 7.

x divides into 120x 120 times. Multiplying all of x- 5 by 120 and subtracting, 120x- 7- (120x- 600)= 593.

x- 5 divides into 4x^3+ 2x^2+ 10x- 7 gives a quotient of 4x^2+ 22x+ 120 with a remainder of 593.

primo candidate for synthetic division ...

Code:

5].......4.......2.......10.......-7
.................20......110.....600
---------------------------------------
.........4.......22......120.....593

quotient ...

Or let:





.

Comparing the coefficients:

, ,

and finally the remainder .

So

Hello, ejaykasai!

You want Long Division? . . . Here it is . . .


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