Identify the rational function whose graph is shown in the figure.
Choices are
f(x) = (3x+5)/(x+1)
f(x) = (x+5)/(x+3)
f(x) = (3x-5)/(x-1)
f(x) = (x+5)/(x+1)
I think the answer is f(x) = (3x-5)/(x-1). can someone please check my answer.
Identify the rational function whose graph is shown in the figure.
Choices are
f(x) = (3x+5)/(x+1)
f(x) = (x+5)/(x+3)
f(x) = (3x-5)/(x-1)
f(x) = (x+5)/(x+1)
I think the answer is f(x) = (3x-5)/(x-1). can someone please check my answer.
the graph is
vertical asymptotes occur when the function is undefined. we see one occurs when x = -1, so we want one of the graphs where the denominator is zero when x = -1. so the first and the last graphs are the possible choices. how do we know which to choose?
from the horizontal asymptote of course. since the degree of the numerator is equal to the degree of the denominator, the horizontal asymptote is given by the ratio of the leading coefficients, which for the first is 3/1 = 3 as is in the graph
If you are so inclined, see http://www.mathhelpforum.com/math-he...-help-plz.html for more information on vertical and horizontal asymptotes