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Math Help - Any help would be greatly appreciated

  1. #1
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    Any help would be greatly appreciated

    The figure shows the graph of the polynomial function y = f(x). For
    which of the values k = 0, 1, 2, or 3 will the equation f(x) = k have
    complex roots?


    The choices are 0, 1, 2, or 3
    Attached Thumbnails Attached Thumbnails Any help would be greatly appreciated-algebra-pic-21.jpg  
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  2. #2
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    For k = 3 because the curve hits it once. We need 2 more solutions. Which the curve does not show because they are not real rather complex.
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  3. #3
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by wvmcanelly@cableone.net View Post
    The figure shows the graph of the polynomial function y = f(x). For
    which of the values k = 0, 1, 2, or 3 will the equation f(x) = k have
    complex roots?


    The choices are 0, 1, 2, or 3
    I'd say k = 3

    then we would have:

    f(x) = 3

    \Rightarrow f(x) - 3 = 0

    However, the graph of f(x) - 3 will cut the x-axis at in one place. Since it is a cubic polynomial, we should get 3 roots, since we would have only 1 real root if we shift the graph 3 units down, the other two roots will be complex


    EDIT: Beaten yet again!
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  4. #4
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    thanks for the quick response. I had 3 but was not sure.

    Greatly appreciated
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