Any help would be greatly appreciated

The figure shows the graph of the polynomial function y = f(x). For
which of the values k = 0, 1, 2, or 3 will the equation f(x) = k have
complex roots?


The choices are 0, 1, 2, or 3

For k = 3 because the curve hits it once. We need 2 more solutions. Which the curve does not show because they are not real rather complex.

Quote:

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Originally Posted by wvmcanelly@cableone.net

The figure shows the graph of the polynomial function y = f(x). For
which of the values k = 0, 1, 2, or 3 will the equation f(x) = k have
complex roots?


The choices are 0, 1, 2, or 3

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I'd say k = 3

then we would have:





However, the graph of will cut the -axis at in one place. Since it is a cubic polynomial, we should get 3 roots, since we would have only 1 real root if we shift the graph 3 units down, the other two roots will be complex


EDIT: Beaten yet again!

thanks for the quick response. I had 3 but was not sure.

Greatly appreciated