Hi, How would I graph this function please?
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Originally Posted by wolfhound Hi, How would I graph this function please? what you posted is equivalent to or did you really mean this ... ?
Originally Posted by skeeter what you posted is equivalent to Hi, its this one, but I dont know what to do?
graph has a vertical asymptote and a slant asymptote ... start by finding and graphing them.
i don't know how sorry
Originally Posted by wolfhound i don't know how sorry Use long division: Code: 36 x^2 ÷ (x - 6) = x + 6 + ----- -(x^2 - 6x) x-6 ------------- 6x -(6x - 36) ---------- 36 That means: Keep in mind that a denominator must unequal zero.
36 x^2 ÷ (x - 6) = x + 6 + ----- -(x^2 - 6x) x-6 ------------- 6x -(6x - 36) ---------- 36
Originally Posted by earboth Use long division: Code: 36 x^2 ÷ (x - 6) = x + 6 + ----- -(x^2 - 6x) x-6 ------------- 6x -(6x - 36) ---------- 36 That means: Keep in mind that a denominator must unequal zero. Oh thanks, but I still don't know how to graph it
Originally Posted by wolfhound Oh thanks, but I still don't know how to graph it have you had any instruction on the graphing of rational functions? if not, then you need to research the topic and do some example problems. here's a link to get you started ... http://www.mathmotivation.com/lectur...-Functions.pdf
No ,I haven't been taught anything about the graphing of them. The question I got asked me to identify if the parabola is U or n shaped.( i know -x^2 means n shape) But i want to understand the whole concept of it... thanks
Originally Posted by wolfhound Hi, How would I graph this function please? where did this original equation come from?
on the question sheet
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