Thread: how to solve equations with variables as exponents?

What steps would I have to do to solve an equation such as 2 x 3 = 7 x 5^x and 4.6 x 1.06^(2x + 3) = 5 x 3^x

if you could answer in the simplest way you can it would be greatly appreciated.

Originally Posted by yolanda

What steps would I have to do to solve an equation such as 2 x 3 = 7 x 5^x and 4.6 x 1.06^(2x + 3) = 5 x 3^x

if you could answer in the simplest way you can it would be greatly appreciated.

use logarithms, do you know how?

btw, using "x" for variables and multiplication signs (which is what i think you're doing) is a bad idea.

I don't know how, which is why I asked

consider
a^x = b
(write it on paper)
we can make b the subject, which is above
we can make a the subject, which will be: a = b^(1/x)
however, to make x the subject there is a notation: logs

so x is the power by which we raise a to get b.
the notation is logab=x
note: the a is subscript

So make 5^x the subject first
so assuming u got 5^x = s, where s is a number
so x is the power by which we raise 5 to get s
ie x=log5s

Now u can use an advanced calculator

:'( i hate math

did u solve it then