What steps would I have to do to solve an equation such as 2 x 3 = 7 x 5^x and 4.6 x 1.06^(2x + 3) = 5 x 3^x

if you could answer in the simplest way you can it would be greatly appreciated. :)

Printable View

- October 11th 2010, 08:35 AMyolandahow to solve equations with variables as exponents?
What steps would I have to do to solve an equation such as 2 x 3 = 7 x 5^x and 4.6 x 1.06^(2x + 3) = 5 x 3^x

if you could answer in the simplest way you can it would be greatly appreciated. :) - October 11th 2010, 08:41 AMJhevon
- October 11th 2010, 09:23 AMyolanda
I don't know how, which is why I asked

- October 11th 2010, 09:47 AMzeeshahmad
consider

a^x = b

(write it on paper)

we can make b the subject, which is above

we can make a the subject, which will be: a = b^(1/x)

however, to make x the subject there is a notation: logs

so x is the power by which we raise a to get b.

the notation is logab=x

note: the a is subscript

So make 5^x the subject first

so assuming u got 5^x = s, where s is a number

so x is the power by which we raise 5 to get s

ie x=log5s

Now u can use an advanced calculator - October 11th 2010, 12:13 PMyolanda
:'( i hate math

- October 11th 2010, 12:15 PMzeeshahmad
did u solve it then