A rectangle is placed under the parabolic arch given byf(x) = 27 –

3x2 by using a point (x,y) on the parabola, as shown in the figure.

Write a formula for the functionA(x) that gives the area of the

rectangle as a function of thex-coordinate of the point chosen.

a.f(x) = 6(27 – 3x2)

b .f(x) = 27x– 3x3

c .f(x) = 54x– 6x3

d .f(x) = 162x– 6x3

Algebra is my weakness. Please help.