Results 1 to 2 of 2

Thread: Calculating limit

  1. October 10th 2010, 09:12 AM #1
    Neconine
    Neconine is offline
    Newbie
    Joined
    Nov 2009
    Posts
    11

    Calculating limit

    Not sure how to do this limit, I was thinking of rationalizing the denominator but that didn't work.


    \lim_{x \to -4} \frac{1}{\sqrt{x^2+16}}
    Follow Math Help Forum on Facebook and Google+
  2. October 10th 2010, 09:17 AM #2
    Plato
    Plato is online now
    MHF Contributor
    Joined
    Aug 2006
    Posts
    17,001
    Thanks
    776
    Awards
    1
    MHF Donor
    There is no reason to do that.
    \displaystyle \lim _{x \to - 4} \sqrt {x^2 + 16} = 4\sqrt 2
    Follow Math Help Forum on Facebook and Google+
« Given a complex polynomial and one of its zeroes, find all zeroes of the function | Help Needed Understanding Logs »

Similar Math Help Forum Discussions

  1. calculating a limit
    Posted in the Calculus Forum
    Replies: 2
    Last Post: April 10th 2011, 05:37 PM
  2. calculating the limit
    Posted in the Calculus Forum
    Replies: 3
    Last Post: December 14th 2010, 11:36 AM
  3. Calculating a Limit
    Posted in the Calculus Forum
    Replies: 8
    Last Post: November 1st 2010, 02:16 PM
  4. Need help Calculating the limit?
    Posted in the Calculus Forum
    Replies: 1
    Last Post: October 4th 2010, 04:18 PM
  5. need help on calculating a limit.
    Posted in the Calculus Forum
    Replies: 4
    Last Post: July 4th 2006, 06:49 AM

Search Tags


/mathhelpforum @mathhelpforum