Not sure how to do this limit, I was thinking of rationalizing the denominator but that didn't work. $\displaystyle \lim_{x \to -4} \frac{1}{\sqrt{x^2+16}}$
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There is no reason to do that. $\displaystyle \displaystyle \lim _{x \to - 4} \sqrt {x^2 + 16} = 4\sqrt 2 $
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