Not sure how to do this limit, I was thinking of rationalizing the denominator but that didn't work.

$\displaystyle \lim_{x \to -4} \frac{1}{\sqrt{x^2+16}}$

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- Oct 10th 2010, 09:12 AMNeconineCalculating limit
Not sure how to do this limit, I was thinking of rationalizing the denominator but that didn't work.

$\displaystyle \lim_{x \to -4} \frac{1}{\sqrt{x^2+16}}$ - Oct 10th 2010, 09:17 AMPlato
There is no reason to do that.

$\displaystyle \displaystyle \lim _{x \to - 4} \sqrt {x^2 + 16} = 4\sqrt 2 $