For each question below, tell whether the set of ordered pairs (x,y) defined by each equation is a function.

(a) x + 2y^2 = 1

(b) y = (2/x)

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- Jun 11th 2007, 01:56 PMblueridgeOrdered Pairs (x,y)
For each question below, tell whether the set of ordered pairs (x,y) defined by each equation is a function.

(a) x + 2y^2 = 1

(b) y = (2/x) - Jun 11th 2007, 02:11 PMJhevon
- Jun 11th 2007, 03:25 PMThePerfectHackerQuote:

(a) x + 2y^2 = 1

Both work. For the same x we get more than one y. - Jun 11th 2007, 05:00 PMblueridgetell me...
What do you mean that both work?

Are these one-to-one functions?

Where did you get those values in terms of (x,y)? - Jun 11th 2007, 05:04 PMJhevon
he found a single value for x that maps to two values of y, so it is not a function, since both y's work for 1 x

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Are these one-to-one functions?

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Where did you get those values in terms of (x,y)?