If f(x) = (x - B)/(x - A), f(2) = 0 and f(1) is undefined, what are the avlue of A and B?

Does the term "undefined" mean the same as "does not exist"?

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- Jun 11th 2007, 01:52 PMblueridgeValues of A and B
If f(x) = (x - B)/(x - A), f(2) = 0 and f(1) is undefined, what are the avlue of A and B?

Does the term "undefined" mean the same as "does not exist"? - Jun 11th 2007, 02:02 PMJhevon
I had the solution here, but i realize that you dont want answers.

Hint: A fraction is zero if the numerator is zero (given its denominator is not zero at the same time), a fraction is undefined if the denominator is zero.

Quote:

Does the term "undefined" mean the same as "does not exist"?

- Jun 11th 2007, 04:58 PMblueridgeok
Can you show me step by step what to do leading to the correct answer?

- Jun 11th 2007, 05:09 PMJhevon
- Jun 11th 2007, 05:43 PMblueridgeok
I have not been able to find A and B.

Sorry.... - Jun 11th 2007, 05:47 PMtopsquark
Well there is only one value of A that will make f(1) undefined:

If the denomintator is 0 then the expression is undefined.

So set x - A = 0 when x = 1.

Thus

1 - A = 0 ==> A = 1.

So the expression is

We also know that f(2) = 0. The expression is 0 when the numerator is 0. So set x - B = 0 when x = 2.

Thus

2 - B = 0 ==> B = 2.

So the expression is

-Dan - Jun 11th 2007, 05:51 PMJhevon

Now we are told that f(2) = 0.

I also told you that a fraction is zero if the numerator is zero (provided the denominator isn't zero at the same time)

so this means

Now and we are told this is undefined. i told you a fraction is undefined if we divide by zero. so this means