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Math Help - Logarithm

  1. #1
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    Logarithm

    Hi,

    Are there alternative ways of solving this equation? Could logarithms be used?

    a^{60} = 2.044 \implies a = 2.044^{1/60} = 1.012
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  2. #2
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    Quote Originally Posted by Hellbent View Post
    Hi,

    Are there alternative ways of solving this equation? Could logarithms be used?

    a^{60} = 2.044 \implies a = 2.044^{1/60} = 1.012
    logs could be used ... but the way you did it more direct.
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  3. #3
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    I need assistance with the logs part, please.
    Tried using logs prior to posting question, but the answers are inconsistent.
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  4. #4
    Super Member bigwave's Avatar
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    Quote Originally Posted by Hellbent View Post
    Hi,

    Are there alternative ways of solving this equation? Could logarithms be used?

    a^{60} = 2.044 \implies a = 2.044^{1/60} = 1.012
    60\log{a} = \log{2.044}

    \log{a} = \frac{log{2.044}}{60}<br />
\RightArrow<br />
= .00517<br />

    so 10^{(.00517)} = 1.01199 or 1.012

    as mentioned your first method is better..
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  5. #5
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    a^{60} = k , where k = 2.044

    60\log{a} = \log{k}<br />

    \displaystyle \log{a} = \frac{\log{k}}{60}

    \displaystyle a = e^{\frac{\log{k}}{60}}

    a \approx 1.012

    note that \displaystyle a = e^{\frac{\log{k}}{60}} = \left(e^{\log{k}}\right)^{\frac{1}{60}} = k^{\frac{1}{60}} = 2.044^{\frac{1}{60}}
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