Hi,

Are there alternative ways of solving this equation? Could logarithms be used?

$\displaystyle a^{60} = 2.044 \implies a = 2.044^{1/60} = 1.012$

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- Oct 4th 2010, 04:27 PMHellbentLogarithm
Hi,

Are there alternative ways of solving this equation? Could logarithms be used?

$\displaystyle a^{60} = 2.044 \implies a = 2.044^{1/60} = 1.012$ - Oct 4th 2010, 04:31 PMskeeter
- Oct 4th 2010, 04:38 PMHellbent
I need assistance with the logs part, please.

Tried using logs prior to posting question, but the answers are inconsistent. - Oct 4th 2010, 04:51 PMbigwave
- Oct 4th 2010, 04:53 PMskeeter
$\displaystyle a^{60} = k$ , where $\displaystyle k = 2.044$

$\displaystyle 60\log{a} = \log{k}

$

$\displaystyle \displaystyle \log{a} = \frac{\log{k}}{60}$

$\displaystyle \displaystyle a = e^{\frac{\log{k}}{60}}$

$\displaystyle a \approx 1.012$

note that $\displaystyle \displaystyle a = e^{\frac{\log{k}}{60}} = \left(e^{\log{k}}\right)^{\frac{1}{60}} = k^{\frac{1}{60}} = 2.044^{\frac{1}{60}}$