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Math Help - Solving ln Equations

  1. #1
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    Solving ln Equations

    I don't fully understand how "ln" works yet. I would really appreciate some help with this problem.

    Enter all admissible solutions for:

    ln(x+31)−ln(x+3)=ln(8)−ln(x).
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  2. #2
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    Quote Originally Posted by mmfoxall View Post
    I don't fully understand how "ln" works yet. I would really appreciate some help with this problem.

    Enter all admissible solutions for:

    ln(x+31)−ln(x+3)=ln(8)−ln(x).
    \ln(x+31) - \ln(x+3) = \ln(8) - \ln(x)

    using the difference property for logs ...

    \displaystyle \ln\left(\frac{x+31}{x+3}\right) = \ln\left(\frac{8}{x}\right)

    \displaystyle \frac{x+31}{x+3} = \frac{8}{x}

    solve for x ... note that any solution for x must be greater than zero.
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