1) lim f(x) =2 where x->3 and f(3) exists 2) lim f(x) =2 where x->3 but f(3) does not exist 3) lim f(x) =2 where x->3 and is infinite (does not exist) 4) lim f(x) =2 where x->3- but lim f(x) where x->3+ does not exist
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Originally Posted by yess 1) lim f(x) =2 where x->3 and f(3) exists 2) lim f(x) =2 where x->3 but f(3) does not exist 3) lim f(x) =2 where x->3 and is infinite (does not exist) 4) lim f(x) =2 where x->3- but lim f(x) where x->3+ does not exist I recommend thinking graphically. I also recommend showing some work and saying where you got stuck.
Originally Posted by undefined I recommend thinking graphically. I also recommend showing some work and saying where you got stuck. the problem is i have noooo idea where to start!!
Originally Posted by yess the problem is i have noooo idea where to start!! Here's another idea then. Think of some common functions like f(x)=x. Does this function satisfy (1)? How about (2)?
for 1) i have f(x) = 3x + 3 is that ok??
Originally Posted by yess for 1) i have f(x) = 3x + 3 is that ok?? Why would you think ? It's way off. Hint: For (1) just choose any function that is continuous everywhere and that satisfies f(3)=2. (Note: What I wrote at first wasn't quite right, I edited it.)
Originally Posted by undefined Why would you think ? It's way off. Hint: For (1) just choose any function that is defined everywhere and where f(3)=2. ooooh it makes more sense looking at it like that! soo maybe x-1 ??
Originally Posted by yess ooooh it makes more sense looking at it like that! soo maybe x-1 ?? Yep that works.
so i've got all but 2) .. any hints??
Originally Posted by yess so i've got all but 2) .. any hints?? Draw the graph for f(x)=x-1 except that where x=3 draw a hollow circle..
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