If the point (6,-12) is on the graph of y=f(x), which point must be on the graph of y=f(-1/3x+6).

a) -36,-12

b) -24,-12

c) 0,-12

d) 16,-12

I've tried taking the x, which is 6, dividing it by -1/3 and then moving it 6 to the left, but that doesn't work. Any advice would be amazing.