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Math Help - Inequality

  1. #1
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    Inequality

    Show that 1<\sqrt[n]{a}<\frac {n+(a-1)}n if a>1 and n\in\mathbb{N}\setminus\{1\}.
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  2. #2
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    That \sqrt[n]{a}>1 is easy to see. For the second inequality, \sqrt[n]{a}<\frac {n+(a-1)}n\iff a<(1+(a-1)/n)^n. The latter can be shown using the binomial theorem, according to which (1+x)^n=1+nx+\dots>1+x.

    In fact, the whole power of the theorem is not needed. One can write (1+x)^n as (1+x)\cdot(1+x)\cdot\;\dots\;\cdot(1+x). When performing the multiplication, we have to pick either 1 or x from each factor, and consider and add all such variants. There is only one way to choose 1 from every factor; all other terms will have x in them. Then we can choose x from the first factor and 1's from all the rest, or x from the second factor and 1's from all the rest, etc. In the sum, this will give us nx. All the rest terms in the sum will have at leat x^2.
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