1. ## Matrix question

Thank you everyone!

2. Originally Posted by Oasis1993

Thank you everyone!

$\displaystyle 2x-z=1 \Rightarrow z = 2x-1$

$\displaystyle 4y+az = -3 \Rightarrow 4y + a (2x-1) = -3 \Rightarrow 4y+2ax-a = -3$

$\displaystyle 9x-5y-7z=2 \Rightarrow 9x-5y -7(2x-1) = 2 \Rightarrow 9x-5y-14x+7 = 2$

so now you have

$\displaystyle 2ax+4y =a -3$

$\displaystyle -5x-5y = -5$

can you continue from here ?

P.S. you should get something like :

$\displaystyle \displaystyle x = \frac {a-7}{2(a-2)}$

$\displaystyle \displaystyle y= \frac {a+3}{2 (a-2)}$

$\displaystyle \displaystyle z=- \frac {5}{a-2}$

of course $\displaystyle a\neq 2$

3. hey! thanks so much for the reply, it's clearer to me now..however i don't understand how you reached those answers?
I'd appreciate if you continued.

thanks again.

4. Originally Posted by Oasis1993
hey! thanks so much for the reply, it's clearer to me now..however i don't understand how you reached those answers?
I'd appreciate if you continued.

thanks again.
show what have you done... than well see where is the problem