algebraically simplify [f(x+deltax)-f(x)]/delta x to -1/[(x+delta x-3)(x-3)] for f(x) = (x-2)/(x-3)
Hello, yess!
When working with a Difference Quotient, I make three steps out of it. .**
. . [1] Find . . . Replace with ... and simplify.
. . [2] Subtract . . . Subtract the original function ... and simplify.
. . [3] Divide by . . . Write in the denominator ... and reduce.
Here we go . . .
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Am I the only teacher on the entire planet who taught it this way?