algebraically simplify [f(x+deltax)-f(x)]/delta x to -1/[(x+delta x-3)(x-3)] for f(x) = (x-2)/(x-3)

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- Sep 23rd 2010, 09:37 AMyess[f(x+deltax)-f(x)]/delta x
algebraically simplify [f(x+deltax)-f(x)]/delta x to -1/[(x+delta x-3)(x-3)] for f(x) = (x-2)/(x-3)

- Sep 23rd 2010, 01:58 PMSoroban
Hello, yess!

Quote:

When working with a Difference Quotient, I make*three*__steps__

. . [1] Find . . . Replace with ... and simplify.

. . [2] Subtract . . . Subtract the original function ... and simplify.

. . [3] Divide by . . . Write in the denominator ... and reduce.

Here we go . . .

. .

. .

. .

. . . . . . . . . . . . . . . . .

~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~

**

Am I the only teacher on the entire planet who taught it this way?