this should be easy but keep getting different answers every time I do it.
multiplied eq1 by 3 and eq2 by 5 to get
multiply thru by 3
before deriving y using x it is hard to believe that this value is correct??
actually, it was sugested that when fractions show in simultanious equations that it is best to multiply or cancel them out as an easy way to do it... however I see your point in that -2 would of left the fractions but the x would of canceled... quess the y would not of been that hard to get... yes i always seem to introduce error with a lot of steps
yep, you are right, when I ploted them they were not lines. I presume this is because the y is in the denominator making it rational resulting a graph with an asymptotes.
I did try to make this into the but of course cannot.
however the text did say they were linear equations but doesn't look like it.
interesting catch not sure where the red flag was.