Originally Posted by

**bigwave** this should be easy but keep getting different answers every time I do it.

$\displaystyle 2x + \frac{5}{y} = -11$

$\displaystyle 4x-\frac{3}{y}=\frac{21}{3}$

multiplied eq1 by 3 and eq2 by 5 to get

$\displaystyle 6x+\frac{15}{y} = -33$

$\displaystyle 20x-\frac{15}{y}=\frac{105}{3}$

adding gives

$\displaystyle 26x = -33 + \frac{105}{3}$

multiply thru by 3

$\displaystyle 78x = -99 + 105 = 6$

$\displaystyle x = \frac{6}{78} $

before deriving y using x it is hard to believe that this value is correct??