Hello, I'm having a lot of trouble solving the following problem:

Treating the, $\displaystyle 4+4x+2y+5x^2+3xy+4y^2=0$ as a quadratic equation in $\displaystyle x$ with coefficients in terms of $\displaystyle y$, solve for $\displaystyle x$.
Any help would be greatly appreciates

Thanks

2. Originally Posted by spoc21
Hello, I'm having a lot of trouble solving the following problem:

Treating the, $\displaystyle 4+4x+2y+5x^2+3xy+4y^2=0$ as a quadratic equation in $\displaystyle x$ with coefficients in terms of $\displaystyle y$, solve for $\displaystyle x$.
Any help would be greatly appreciates

Thanks
Re-arranging: $\displaystyle 5x^2 + (4 + 3y)x + (4y^2 + 2y + 4) = 0$.

a = ..., b = ....., c = ......

Substitute into the quadratic formula etc.

I'm getting a very strange solution:x = $\displaystyle 4y^2-3y+4$..I'm still not sure if my method is correct. I was wondering if you could please explain this problem, so that I can learn from this..
I'm getting a very strange solution:x = $\displaystyle 4y^2-3y+4$..I'm still not sure if my method is correct. I was wondering if you could please explain this problem, so that I can learn from this..