• Sep 20th 2010, 07:39 PM
spoc21
Hello, I'm having a lot of trouble solving the following problem:

Treating the, $4+4x+2y+5x^2+3xy+4y^2=0$ as a quadratic equation in $x$ with coefficients in terms of $y$, solve for $x$.
Any help would be greatly appreciates

Thanks
• Sep 20th 2010, 07:43 PM
mr fantastic
Quote:

Originally Posted by spoc21
Hello, I'm having a lot of trouble solving the following problem:

Treating the, $4+4x+2y+5x^2+3xy+4y^2=0$ as a quadratic equation in $x$ with coefficients in terms of $y$, solve for $x$.
Any help would be greatly appreciates

Thanks

Re-arranging: $5x^2 + (4 + 3y)x + (4y^2 + 2y + 4) = 0$.

a = ..., b = ....., c = ......

Substitute into the quadratic formula etc.
• Sep 20th 2010, 08:53 PM
spoc21
I'm getting a very strange solution:x = $4y^2-3y+4$..I'm still not sure if my method is correct. I was wondering if you could please explain this problem, so that I can learn from this..

thanks :)
• Sep 20th 2010, 10:06 PM
mr fantastic
Quote:

Originally Posted by spoc21
I'm getting a very strange solution:x = $4y^2-3y+4$..I'm still not sure if my method is correct. I was wondering if you could please explain this problem, so that I can learn from this..