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Math Help - diameter of a circle

  1. #1
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    Post diameter of a circle

    Suppose AB is the diameter of a circle, where A = (-1,-3) and B = (3,-2). The equation of the circle is?

    4(x-1)^2 +4(y+5/2)^2 =17
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  2. #2
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    Quote Originally Posted by Alexander View Post
    Suppose AB is the diameter of a circle, where A = (-1,-3) and B = (3,-2). The equation of the circle is?

    4(x-1)^2 +4(y+5/2)^2 =17
    I will give you the steps. I will not do your homework for you.

    1)Find the midpoint between A(-1,-3) \mbox{ and }B(3,-2). Use the midpoint formula (see below).

    2)The answer to #1 is the center of circle.

    3)Find the length between A(-1,-3)\mbox{ and }B(3,-2). Use the distance formula (see below).

    4)The answer to #4 is diamter length, find half of it.

    5)You know the center of circle and its radius. You can now describe its equation.

    ---
    Midpoint formula: \left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2} \right)

    Distance formula: \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}
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