Hello I am having difficulty solving this question. Any help would be greatly appreciated.
$\displaystyle g(x)=3+x+e^x$
The e is the mathematical constant not a variable
find $\displaystyle g^{-1}(4)$
So I must find a value of x where g(x)=4
this is my attempt:
$\displaystyle 4=3+x+e^x$
$\displaystyle 1=x+e^x$
$\displaystyle 1-x=e^x$
I know that ln(e^x)=x so I thought of doing that
ln(1-x)=x
But I don't know what to do after that. Thanks for the assistance.