The circle with equation x^2 + 4x + y^2 - 6y = 3 has center C and radius r, where? C = (0,0) ; r = Ö3C = (2, -3) ; r = 16C = (2, -3) ; r = 4C = (-2,3) ; r = 16C = (-2,3) ; r = 4
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The circle's equation is: Rearrange this using the "identities" and you'll find it changes to: Compare it with the general form for a circle, radius centred at : and you can see that , and the centre is .
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