use a graphing utility to approximate the real solutions, if any, of each equation rounded to two decimal places. all solutions lie between -10 and 10

x^3 - 8x + 1 = 1

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- Sep 14th 2010, 01:08 PMblfanGraphical solutions to x^3 - 8x + 1 = 1
use a graphing utility to approximate the real solutions, if any, of each equation rounded to two decimal places. all solutions lie between -10 and 10

x^3 - 8x + 1 = 1 - Sep 14th 2010, 01:13 PMundefined
- Sep 14th 2010, 01:20 PMe^(i*pi)
This one isn't too hard to solve algebraically but nonetheless put the graph of and look for y intercepts which will be the roots of the equation.

Algebra gives solutions of

See attached graph (done in kmplot) Attachment 18921