"(i) decompose the following expression into partial fractions and

(ii) check your answer by multiplying them out

6x + 7/ 3x (x +1)

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- Sep 14th 2010, 10:06 AMporge111partial fractions question
"(i) decompose the following expression into partial fractions and

(ii) check your answer by multiplying them out

6x + 7/ 3x (x +1) - Sep 14th 2010, 11:09 AMe^(i*pi)
- Sep 14th 2010, 11:32 AMmasters
Or...you could multiply everything through, group the x terms and the constant terms:

$\displaystyle 6x+7=Ax+A(1)+3Bx$

$\displaystyle 6(x)+7(1)=(A+3B)x+A(1)$

For the two sides to be equal, the coefficients of the two polynomials must be equal. So you "equate the coefficients":

$\displaystyle A+3B=6$ and $\displaystyle A=7$

B is easy to find after that. - Sep 14th 2010, 11:47 AMwonderboy1953