Attachment 18904

With the help of technology I've figured out that r=27 but I can't quite work it out.

I know 2^3log4(3)=2^log4(27 or 2^(log27)/(log4) and sqrt(r)=r^(1/2) but I can't quite put it all together....

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- Sep 12th 2010, 10:04 AMmetaname90Solving equation with logs
Attachment 18904

With the help of technology I've figured out that r=27 but I can't quite work it out.

I know 2^3log4(3)=2^log4(27 or 2^(log27)/(log4) and sqrt(r)=r^(1/2) but I can't quite put it all together.... - Sep 12th 2010, 10:23 AMPlato
First notice that

Then .

Take the log of both - Sep 12th 2010, 01:30 PMSoroban
Hello, metaname90!

Quote:

The left side is: .

Since

. . we have: .

The equation becomes: .