a) f(x) = 17 + 3x^2 - 13x^3 - 6x^4

b) f(x) = (5x^2-7x+2)/(4x^2-2)

c) e^x

all of them are asking for two answers. the first as x to -infinity and the second as x to infinity.

thank you thank you =)

Printable View

- Sep 8th 2010, 07:27 PMmelliepDetermine the end behavior of each function...?
a) f(x) = 17 + 3x^2 - 13x^3 - 6x^4

b) f(x) = (5x^2-7x+2)/(4x^2-2)

c) e^x

all of them are asking for two answers. the first as x to -infinity and the second as x to infinity.

thank you thank you =) - Sep 8th 2010, 07:37 PMundefined
Have you done these kinds of limits before?

a) Which term dominates the others as x approaches +/- infinity?

b) Which term in denominator dominates, which term in numerator..?

c) If it's not obvious.. which I guess it's not since you're asking.. just graph it. Then justify it. - Sep 8th 2010, 07:42 PMmr fantastic
- Sep 8th 2010, 08:04 PMmelliep
mmm I'm really sorry that doesn't help me.

I've never learned this before and I'm expected to since I'm in adv. calc. - Sep 8th 2010, 08:05 PMundefined
Yet another way to handle (b) is

(x won't be 0)

$\displaystyle \displaystyle \frac{5x^2-7x+2}{4x^2-2}=\frac{\frac{1}{x^2}(5x^2-7x+2)}{\frac{1}{x^2}(4x^2-2)}=\frac{5-\frac{7}{x}+\frac{2}{x^2}}{4-\frac{2}{x^2}}$ - Sep 8th 2010, 08:13 PMundefined
This might help, I found it w/ google search and seems good at a glance

Limits to Infinity - Sep 9th 2010, 03:00 AMmr fantastic
- Sep 15th 2010, 10:40 PMmelliep
Hahaha...thanks...

Mmm because I'm smart, maybe?

And because I'm good at taking tests.

Sorry if my question was not up to par.

Thanks for your help.