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Math Help - Give a possible formula for this 4th-degree polynomial...

  1. #1
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    Give a possible formula for this 4th-degree polynomial...

    Assume the graph of a 4th-degree polynomial crosses the x-axis at exactly -2, 2, and 5. Let k be the leading coefficient with k > 0.

    Give a possible formula for this 4th-degree polynomial.
    Last edited by mr fantastic; September 8th 2010 at 07:36 PM. Reason: Copied title into main body of post.
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  2. #2
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    Quote Originally Posted by melliep View Post
    Assume the graph of a 4th-degree polynomial crosses the x-axis at exactly -2, 2, and 5. Let k be the leading coefficient with k > 0.
    P(x)=k(x+2)^a(x-2)^b(x-5)^c

    let (a,b,c)=(1,1,2) or (1,2,1) or (2,1,1)
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  3. #3
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    I tried that, it was incorrect =(
    Nothing I do is working.
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  4. #4
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    Quote Originally Posted by melliep View Post
    I tried that, it was incorrect =(
    Nothing I do is working.
    Was it rejected by an automatic computer checker? Was it marked incorrect by a teacher? Did it not match an answer key? If you were expected to expand, are you sure you did it without making mistakes?

    Because it certainly looks correct from where I'm standing..
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  5. #5
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    it was rejected on online homework.
    haha, yes I input it correctly, I'm sure.
    I'm not sure why it's consistently wrong. But thank you very much.
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  6. #6
    MHF Contributor undefined's Avatar
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    Quote Originally Posted by melliep View Post
    it was rejected on online homework.
    haha, yes I input it correctly, I'm sure.
    I'm not sure why it's consistently wrong. But thank you very much.
    Try posting a screenshot of your submission if you can. I'm curious about this.

    Edit: Does this homework count towards your grade? If so it's against forum rules for me to help. Nevertheless, since we've already gone over the answer, I'm still curious why the answer would be rejected by the checker.
    Last edited by undefined; September 8th 2010 at 08:51 PM.
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