Assume the graph of a 4th-degree polynomial crosses thex-axis at exactly -2, 2, and 5. Letkbe the leading coefficient withk> 0.

Give a possible formula for this 4th-degree polynomial.

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- September 8th 2010, 07:24 PMmelliepGive a possible formula for this 4th-degree polynomial...
Assume the graph of a 4th-degree polynomial crosses the

*x*-axis at exactly -2, 2, and 5. Let*k*be the leading coefficient with*k*> 0.

Give a possible formula for this 4th-degree polynomial. - September 8th 2010, 07:29 PMundefined
- September 8th 2010, 08:05 PMmelliep
I tried that, it was incorrect =(

Nothing I do is working. - September 8th 2010, 08:10 PMundefined
- September 8th 2010, 08:27 PMmelliep
it was rejected on online homework.

haha, yes I input it correctly, I'm sure.

I'm not sure why it's consistently wrong. But thank you very much. - September 8th 2010, 08:32 PMundefined
Try posting a screenshot of your submission if you can. I'm curious about this.

Edit: Does this homework count towards your grade? If so it's against forum rules for me to help. Nevertheless, since we've already gone over the answer, I'm still curious why the answer would be rejected by the checker.