If f(x)=2x^2-3x+1, find the simplified expression for g(x) in g(x)= f(2x).
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Replace every in with . Then simplify.
Let x = 2x for f(x) f(2x) = 2(2x)^2-3(2x)+1 f(2x) = 2(4x^2) - 6x + 1 f(2x) = 8x^2 - 6x + 1 Correct?
Originally Posted by fdrhs1984 Let x = 2x for f(x) f(2x) = 2(2x)^2-3(2x)+1 f(2x) = 2(4x^2) - 6x + 1 f(2x) = 8x^2 - 6x + 1 Correct? Yes, good job.
Great! Thanks a lot.
Originally Posted by fdrhs1984 Let x = 2x for f(x) f(2x) = 2(2x)^2-3(2x)+1 f(2x) = 2(4x^2) - 6x + 1 f(2x) = 8x^2 - 6x + 1 Correct? Yes it is. You could also simplify further by factorising. .
Is this the Grouping Method for factoring?
Originally Posted by fdrhs1984 Is this the Grouping Method for factoring? It most certainly is. Multiply your and values. In this case you get . So you need to think of two numbers that multiply to give and add to give (the value). In this case they are and , which is what you break the middle term into.
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