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Math Help - Find the values at which the function fails to be continuous (trig)

  1. #1
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    Find the values at which the function fails to be continuous (trig)

    find all the values of x at which the function fails to be continuous
    f(x)= 2/(1+cos2x)

    I believe the function fails to be continuous when the denominator equals zero(right?)
    So wouldn't the correct answer be 2n(pi)+(pi/2) for all integers n? The answer keeps coming up as incorrect.

    Could someone please correct me if I'm wrong?
    Thank you! I appreciate the help!
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  2. #2
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    Quote Originally Posted by yzobel View Post
    find all the values of x at which the function fails to be continuous
    f(x)= 2/(1+cos2x)

    I believe the function fails to be continuous when the denominator equals zero(right?)
    So wouldn't the correct answer be 2n(pi)+(pi/2) for all integers n? The answer keeps coming up as incorrect.

    Could someone please correct me if I'm wrong?
    Thank you! I appreciate the help!
    If the denominator is 1 + \cos(2x) , then this function is discontinuous when

    2x = \pm \pi , \pm 3\pi , \pm 5\pi , ...

    x = \frac{\pi}{2} + k\pi \, ; \, k \in \mathbb{Z}
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