Originally Posted by

**watp** Sorry for starting another topic, but I've tried for hours to try and get an answer.

I need to find the point of intersection (which I know is (4,7)), but I don't know how I'm supposed to get there?

$\displaystyle \displaystyle y=- \frac {4x}{3}+12.33 $

$\displaystyle \displaystyle y= \frac {3x}{4}+4 $

$\displaystyle \displaystyle y= \frac {3x}{4}+4 \Rightarrow 4y=3x+16 \Rightarrow 3x=4y-16 \Rightarrow x= \frac {4y-16}{3} $

$\displaystyle \displaystyle y=- \frac {4x}{3}+12.33 $

$\displaystyle \displaystyle y=- \frac {4(\frac {4y-16}{3} )}{3}+12.33 $

$\displaystyle \displaystyle y=- \frac {\frac {16y-64}{3} }{3} +12.33 $

If I move the 4y to the other side? Then do $\displaystyle \frac{-16}{3} + 12.33$, I get 6.9997, but that's for 4y.

What am I doing wrong?

x

$\displaystyle \displaystyle x = \frac {4y-16}{3} $