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Math Help - Hyperbola equation help

  1. #1
    Newbie Zora's Avatar
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    Hyperbola equation help

    Find equation of a hyperbola in standard form with center (-2,5), one vertex at (-2,8) and slope of one of its asymptotes is 3/5
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  2. #2
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    Distance between center and the vertex is a, and equation of asymptote is y = (a/b)x.

    Find a and b from the given information.

    So the equation of the hyperbola is

    \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1
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  3. #3
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    Well, actually, no. If the center is at (x_0, y_0), the distance from the center to a vertex is a, and the equation of the asymptote is y= (b/a)x, the equation of the hyperbola is
    \frac{(x- x_0)^2}{a^2}- \frac{(y- y_0)^2}{b^2}= 1
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