$\displaystyle f(x) = \frac {Sin2x}{1+Sin2x} = 1$

Is my answer correct?

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- Aug 31st 2010, 05:23 PMhydrideSolve the function
$\displaystyle f(x) = \frac {Sin2x}{1+Sin2x} = 1$

Is my answer correct? - Aug 31st 2010, 05:28 PMpickslides
What is your answer?

- Aug 31st 2010, 05:34 PMhydride
1

- Aug 31st 2010, 05:55 PMpickslides
At the moment you have

$\displaystyle \frac {\sin2x}{1+\sin2x} = 1$

This is not solved and neither looks like it can be.

When you solve a function the answer looks like x=...

What is your solution for x? - Aug 31st 2010, 08:23 PMEducated
$\displaystyle f(x) = \dfrac {Sin2x}{1+Sin2x} = 1$

I think hydride is trying to simplify the equation...?

If so, then it is not correct. The current equation of $\displaystyle f(x) = \frac {Sin2x}{1+Sin2x}$ cannot be simplified any more.