# Thread: Finding Range of a function Algebraicly

1. ## Finding Range of a function Algebraicly

The problem says use algebra to find the range of each function, that means no graphs.
$\displaystyle h(y)=y^2-2y-8$$\displaystyle A(stands for all real numbers)=y^2-2y-8$
Solve for Y
Now this is where I get confused...
$\displaystyle A+8=y^2-2y$
That's how far I've gotten, no matter how I subtract, add, divide, the $\displaystyle y^2 or 2y$, I can't solve for Y
I know this is prob. algebra stuff, but that's what gets me the most

2. one way to algebraically find the range of a function is to find the domain of the function's inverse.

3. That's a good idea, and I'll keep the inverse method in mind.
But for this class, he hasn't gone over inverses yet, and he wants us to find the Range that specific way for the homework, where it's set to A and solve for Y.
i def. rather use the graph.