The problem says use algebra to find the range of each function, that means no graphs.

$\displaystyle h(y)=y^2-2y-8$$\displaystyle

A(stands for all real numbers)=y^2-2y-8$

Solve for Y

Now this is where I get confused...

$\displaystyle A+8=y^2-2y$

That's how far I've gotten, no matter how I subtract, add, divide, the $\displaystyle y^2 or 2y$, I can't solve for Y

I know this is prob. algebra stuff, but that's what gets me the most (Speechless)