No, I think it is likely that there are two real roots.

For consider: for x large you have that the second term on the left side is about 1, so you would expect one real solution to be close to 2009.

Also, for x tending to 1 from the right you have that the value of the left side goes to +oo. Hence you can expect another real root to be found close to 1 (but greater than 1).

Based on my above guesswork I would say that option (A) is right.i got options even

(A)2010

(B)4040

(C)1005

(D)0