Heres my attempt: 9B+3C+D=1 9A+6B+C=0 6A+B+3C+D=0 A+C=0 This is what I get for A, B C, and D Where did I go wrong?
Last edited by yoman360; August 28th 2010 at 11:35 AM.
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It seems you missed something while solving simultaneously... Anyway, if you take from here: Putting x = -3 cancels A, B and C all at once, giving: And
your right i made one tiny mistake which messed up the whole thing. >.<
I agree. One slight mistake can ruin the whole thing since there are so many 'variables' to find... Anyway, I then used wolframalpha and got the partial fractions: http://www.wolframalpha.com/input/?i=\frac{1}{(x^2%2B1)(x%2B3)^2}
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