log(base)3 (5x-1)=2 I need help solving this equation. I hope is clear. It's suppose to be log base 3 and 5x-1 is whole term :) thank you for your attention

Printable View

- Aug 20th 2010, 05:36 PMcristinaivelisseLogarithmic equation
log(base)3 (5x-1)=2 I need help solving this equation. I hope is clear. It's suppose to be log base 3 and 5x-1 is whole term :) thank you for your attention

- Aug 20th 2010, 06:03 PMAckbeet
I would say the first thing to do is raise 3 to both sides of the equation thus:

$\displaystyle \displaystyle{3^{\log_{3}(5x-1)}=3^{2}}.$

Can you see where to go from here? - Aug 20th 2010, 06:25 PMcristinaivelisse
I'm sorry (Crying) I have no idea were to go from there. Do I move the log base 3 (5x-1) up front the 3... like:

3 log base 3 (5x-1) and then distribute? - Aug 20th 2010, 06:35 PMskeeter
if $\displaystyle \log_b(a) = c$ , then $\displaystyle b^c = a$

change your log equation to exponential form. - Aug 20th 2010, 11:07 PMEducated