I tried all sorts to get this question pasted or attached by itself but couldn't.
I wonder if anyone would be kind enough go to the link and look at question number 22.
It' page 20 -21 at this link: (If you have DSL it will take 1 min to download)
http://www.aqa.org.uk/qual/gcse/qp-m...W-QP-NOV05.PDF
Thanks.
On your keyboard, just above the "Insert" button, there's a button called "PrtScrn." Go to the page that you need help on in the PDF then click the "PrtScrn" button to "Print Screen" (this is basically a way of "copying" the screen's image which you can then "paste" into MS Paint).
22 The grid on the opposite page shows graphs of a curve
and 3 straight lines
You must use the graphs to answer the following questions.
(a) Write down a pair of simultaneous linear equations that have a solution
Look at the cooresponding graph. Go to the point on the graph, and you will see that two of the lines interesect at this point. The two lines are and .
(b) Write down and simplify a quadratic equation whose solutions are approximately -3.3 or 0.3. You must show clearly how to obtain your answer.
For this, we want the x-intercepts of the quadratic equation to be . For this, we can set up a factored quadratic equation that has these solutions:
this equation has roots and (which is what we want)
(I hope that makes sense to you. I'm not sure how far you are in that class.)
(c) Write down the approximate solutions to the equation . You must show clearly how you obtain your answer.
I notice that this cannot be factored, so I'm thinking we should use the quadratic equation. However, I'm not sure if you've ever seen the quadratic equation. If you haven't, say so and I'm sure someone else can explain this problem differently.
and
for (b) i used the graph by locating the solutions given as intersecting points for two of the graphs, then i equated them and simplified. i verified with the quadratic formula
for (c), we could have constructed the given quadratic using two of the original graphs given. once we figure out which graphs to use, we could look at their intersecting points to find approximations to the solutions