1.$\displaystyle \;\boxed{px^2 - (p-1)x - \dfrac{(p^3-3p+2)}{(p-5)(p-6)}}$ where p>1 is negative for atleast one negative x then p does not belong toSpoiler:

where I --> infinity

Printable View

- Aug 8th 2010, 04:46 PMgrgrsanjaytheory of equations
1.$\displaystyle \;\boxed{px^2 - (p-1)x - \dfrac{(p^3-3p+2)}{(p-5)(p-6)}}$ where p>1 is negative for atleast one negative x then p does not belong to

__Spoiler__:

where I --> infinity